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You are at the section Fun With Math-Superpowerition: Inventing a Super Power Operation

a ✱ 1

Now, let's look at the Superpowerition operation by placing the "1" to the right of the superpowerition notation symbol:

a ✱ 1

Let's try out some variables for a using the formula a ^ (a ^ (b - 1)) as it becomes a ^ (a ^ (1 - 1)).

2 ✱ 1 = 2 ^ (2 ^ (1 - 1)) = 2 ^ (2 ^ 0) = 2 ^ 1 = 2
3 ✱ 1 = 3 ^ (3 ^ (1 - 1)) = 3 ^ (3 ^ 0) = 3 ^ 1 = 3
6 ✱ 1 = 6 ^ (6 ^ (1 - 1)) = 6 ^ (6 ^ 0) = 6 ^ 1 = 6
10 ✱ 1 = 10 ^ (10 ^ (1 - 1)) = 10 ^ (10 ^ 0) = 10 ^ 1 = 10
1,000 ✱ 1 = 1,000 ^ (1,000 ^ (1 - 1)) = 1,000 ^ (1,000 ^ 0) = 1,000 ^ 1 = 1,000

As you can see, a ✱ 1 = a in every case above.

So, then, what does 1 ✱ 1 yield? Let's find out:

1 ✱ 1 = 1 ^ (1 ^ (1 - 1)) = 1 ^ (1 ^ 0) = 1 ^ 1 = 1

As predicted, the answer is "1".

In the exponent rules, n⁰ = 1 (where n > 0), 1ⁿ = 1, and n¹ = n.

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Fun With Math-Superpowerition: Inventing a Super Power Operation Main Page Introduction Comparing The Math Operators I Comparing The Math Operators II Using Numbers 3 and Higher 1 ✱ b a ✱ 1 a ✱ 0 0 ✱ b a ✱ -b -a ✱ b -a ✱ -b Formula Summary So Far Integer a > 1 ✱ Decimal b > 1 Integer a > 1 ✱ Decimal 0 < b < 1 Integer a > 1 ✱ Decimal b < 0 Decimal a > 1 ✱ Decimal b > 1 Decimal a > 1 ✱ Decimal 0 < b < 1 Decimal a > 1 ✱ Decimal b < 0 Decimal 0 < a < 1 ✱ Decimal b > 1 Decimal 0 < a < 1 ✱ Decimal 0 < b < 1 Decimal 0 < a < 1 ✱ Decimal b < 0 Decimal -2 < a < 0 ✱ Decimal -1 < b < 2 Formula Summary So Far II Why 2 ✱ 0 is Not 1 Finding The Inverse Operations 1.25 ✱ -10 to 10 1.5 ✱ -10 to 10 1.75 ✱ -10 to 10 2 ✱ -10 to 10 2.5 ✱ -10 to 10 3 ✱ -10 to 10 3.5 ✱ -10 to 10 4 ✱ -10 to 10 4.5 ✱ -10 to 10 5 ✱ -10 to 10 6 ✱ -10 to 10 7 ✱ -10 to 10 8 ✱ -10 to 10 9 ✱ -10 to 10 10 ✱ -10 to 10
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